Fig. 46 Applied shear stress and material shear strength as a function of depth representing types of fatigue damage. (a) No damage. (b) Subsurface-origin, macropitting fatigue. (c) Micropitting or surface-origin macropitting fatigue. (d) Subcase fatigue. More

Fig. 55 Applied shear stress and material shear strength as a function of depth representing types of fatigue damage. (a) No damage . (b) Subsurface-origin, macropitting fatigue . (c) Micropitting or surface-origin macropitting fatigue . (d) Subcase fatigue More

Fig. 7 Viscosity and shear stress versus shear rate for PDMS (polydimethylsiloxane) from rotational rheometry More

Fig. 1 Definition of (a) average normal stress and (b) average shear stress. F , force (load); V , force parallel to area. More

Fig. 1 Definition of (a) average normal stress and (b) average shear stress. F , force (load); V , force parallel to area More

Fig. 8 Maximum shear stress as a function of displacement for two spring heights. The compressor that exhibited failures had a spring height of 25.0 mm. Lowering the compressor weight reduces the height, thus lowering the maximum stress as a function of lateral displacement. The fatigue bench More

Fig. 86 Fracture on essentially one plane of high shear stress in a 7075-T6 cylindrical tensile specimen. There is a small flat region in the center of the specimen (not visible in photograph) that does not extend to the surface of the specimen. No fracture surface markings exist to indicate More

Fig. 36 Maximum shear stress planes for radial and tangential stresses created by necking. Source: Ref 54 More

Fig. 36 Maximum shear-stress planes for radial and tangential stresses created by necking. Source: Ref 55 More

Fig. 86 Fracture on essentially one plane of high shear stress in a 7075-T6 titanium alloy cylindrical tensile specimen. There is a small flat region in the center of the specimen (not visible in photograph) that does not extend to the surface of the specimen. No fracture-surface markings More

Fig. 47 Effect of sliding or shear stress at the contact interface on the localization of maximum shear stress. Source: Ref 31 More

Fig. 3 Influences of friction coefficients on subsurface principle shear stress: (a) Influence of friction coefficients on maximum principle shear stress along y -axis; and (b) Influence of friction coefficients on maximum principle shear stress along with y / a More

Fig. 4 Influences of friction coefficients on subsurface octahedral shear stress: ( a ) Influence of friction coefficients on octahedral shear stress along y -axis: and ( b ) Influence of friction coefficients on octahedral shear stress along with y / a More

Fig. 1 Free-body diagrams showing orientation of normal stresses and shear stresses in a shaft and the single-overload fracture behavior of ductile and brittle materials. (a) Under simple tension. (b) Under torsion. (c) Under compression loading. See text for discussion. More

Fig. 7 Free-body diagrams showing orientation of normal stresses and shear stresses in a shaft and the single-overload fracture behavior of ductile and brittle materials. (a) Under simple tension. (b) Under torsion. (c) Under compression loading More

Fig. 7 Free-body diagrams showing orientation of normal stresses and shear stresses in a shaft and the single-overload fracture behavior of ductile and brittle materials. (a) Under simple tension. (b) Under torsion. (c) Under compression loading More

Fig. 1 Free-body diagrams showing orientation of normal stresses and shear stresses in a shaft and the single-overload fracture behavior of ductile and brittle materials. (a) Under simple tension. (b) Under torsion. (c) Under compression loading. See text for discussion More

Fig. 2 Schematic figure showing the effect of a normal stress, σ, and a shear stress, τ, on a crystalline material. Application of a normal stress increases the interplanar distance and ultimately results in fracture. Application of a shear stress causes the planes of atoms to slide over each More

Fig. 2 Schematic figure showing the effect of a normal stress, σ, and a shear stress, τ, on a crystalline material. Application of a normal stress increases the interplanar distance and ultimately results in fracture. Application of a shear stress causes the planes of atoms to slide over each More

Fig. 15 Shear stresses produced by a cylindrical roller below the surface of o bearing raceway. Source: Ref 5 More