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shear stress

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Published: 01 June 2019
Fig. 8 Maximum shear stress as a function of displacement for two spring heights. The compressor that exhibited failures had a spring height of 25.0 mm. Lowering the compressor weight reduces the height, thus lowering the maximum stress as a function of lateral displacement. The fatigue bench More
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Published: 01 December 2019
Fig. 3 Influences of friction coefficients on subsurface principle shear stress: (a) Influence of friction coefficients on maximum principle shear stress along y -axis; and (b) Influence of friction coefficients on maximum principle shear stress along with y / a More
Image
Published: 01 December 2019
Fig. 4 Influences of friction coefficients on subsurface octahedral shear stress: ( a ) Influence of friction coefficients on octahedral shear stress along y -axis: and ( b ) Influence of friction coefficients on octahedral shear stress along with y / a More
Series: ASM Failure Analysis Case Histories
Volume: 3
Publisher: ASM International
Published: 01 December 2019
DOI: 10.31399/asm.fach.v03.c9001807
EISBN: 978-1-62708-241-9
... coefficient with the test time,; and ( b ) FWHM along the radii of test samples) Fig. 2 Vary of Δτ xy along with y / a by different friction coefficients Fig. 3 Influences of friction coefficients on subsurface principle shear stress: (a) Influence of friction coefficients on maximum...
Image
Published: 01 June 2019
Fig. 7 Network of adiabatic shear deformation resulting from complex stress state in the gun during detonation. Etched in picral. More
Image
Published: 01 December 2019
Fig. 15 Theoretic curves (Ashby–Verrall model) of logarithm of yield stress/shear modulus versus logarithm of strain rate considering different grain sizes as well as for the steel investigated ( dashed line ) More
Series: ASM Handbook
Volume: 11
Publisher: ASM International
Published: 15 January 2021
DOI: 10.31399/asm.hb.v11.a0006767
EISBN: 978-1-62708-295-2
... analysis of the component is necessary. Stress analysis is initially performed in the design stage of a development project. Frequently, principal stresses and maximum shear stresses are important to the designer because both are used in common failure expressions to calculate maximum load capability (e.g...
Series: ASM Handbook Archive
Volume: 11
Publisher: ASM International
Published: 01 January 2002
DOI: 10.31399/asm.hb.v11.a0003530
EISBN: 978-1-62708-180-1
... be remembered that some parts are designed to fracture under certain circumstances. Not doing so may constitute the failure. Shear pins, for example, are commonly used to protect valuable equipment by acting as mechanical fuses. Stress directors in helicopter gearing are also designed so that if gear tooth...
Series: ASM Failure Analysis Case Histories
Publisher: ASM International
Published: 01 June 2019
DOI: 10.31399/asm.fach.mech.c9001596
EISBN: 978-1-62708-225-9
... spring diameter, d is the diameter of the wire, N is the number of turns, and G is the shear modulus. 5 The uncorrected shear stress is calculated from: (Eq 2) τ x = 8 P D m π d 3  in MPa  where P is the load in N . The corrected stress is obtained by multiplying...
Series: ASM Handbook
Volume: 11B
Publisher: ASM International
Published: 15 May 2022
DOI: 10.31399/asm.hb.v11B.a0006930
EISBN: 978-1-62708-395-9
... parameter Symbol Units Velocity, angular velocity Shear rate γ ˙ 1/sec Displacement, angular displacement Shear strain γ … Force, torque Shear stress σ N/m 2 (Pa) Ratio Symbol Units Viscosity = stress/shear rate η Pa-sec Modulus(t) = stress(t)/strain G...
Series: ASM Handbook Archive
Volume: 11
Publisher: ASM International
Published: 01 January 2002
DOI: 10.31399/asm.hb.v11.a0003563
EISBN: 978-1-62708-180-1
...]</xref> The stress condition associated with RCF is illustrated schematically in Fig. 3 . With any condition of rolling, the maximum stress being applied at or very near the contact area is the shear stress parallel to the rolling surface at some point below the surface. For normally loaded gear teeth...
Image
Published: 01 June 2019
Fig. 9 Schematic diagram showing the addition of the torque (dotted line) due to lateral deflection on the spring during start/stop conditions. The solid line represents the torque due to the compression of the spring. The magnitude of the shear stress associated with the stress conditions More
Series: ASM Failure Analysis Case Histories
Publisher: ASM International
Published: 01 June 2019
DOI: 10.31399/asm.fach.modes.c0091096
EISBN: 978-1-62708-234-1
... by a tensile stress normal to the 45° plane and not by the longitudinal or transverse shear stress that had been expected to cause an overload failure. Examination of the surfaces of one of the pieces of the broken shaft revealed small longitudinal and transverse shear cracks at the smallest diameter...
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Published: 01 June 2019
attack on the base metal. 40×. (e) Nodule on upper surface of middle layer of laser mirror showing failure in a ductile/tensile mode. (f) Nodule from lower surface of middle layer of the mirror showing failure due to compressive/shearing stresses More
Book Chapter

Series: ASM Handbook Archive
Volume: 11
Publisher: ASM International
Published: 01 January 2002
DOI: 10.31399/asm.hb.v11.a0003544
EISBN: 978-1-62708-180-1
... of crack, and the sudden fracture of the remaining cross section. The article discusses the effects of loading and stress distribution on fatigue cracks, and reviews the fatigue behavior of materials when subjected to different loading conditions such as bending and loading. The article examines...
Series: ASM Handbook
Volume: 11
Publisher: ASM International
Published: 15 January 2021
DOI: 10.31399/asm.hb.v11.a0006779
EISBN: 978-1-62708-295-2
..., whereas ductile materials are preferably described with the Gerber parabola. The diagrams for shear stresses (torsion, shear force) must be symmetrical to the y -axis, which leads, for example, to an elliptical failure line with the vertices T u (static torsion strength) and T alt (alternating...
Series: ASM Handbook Archive
Volume: 11
Publisher: ASM International
Published: 01 January 2002
DOI: 10.31399/asm.hb.v11.a0003538
EISBN: 978-1-62708-180-1
... by slip seemed to obey a critical resolved shear stress law (Schmid's law). Single crystals could be made to extensively twin rather easily. Today, Sohnke's law is no longer assumed to be valid (although a normal stress facilitates cleavage), and no critical shear stress law based on external loading has...
Series: ASM Handbook
Volume: 11
Publisher: ASM International
Published: 15 January 2021
DOI: 10.31399/asm.hb.v11.a0006775
EISBN: 978-1-62708-295-2
... a critical resolved shear-stress law (Schmid’s law). Single crystals could be made to extensively twin rather easily. Today (2020), Sohnke’s law is no longer assumed to be valid (although a normal stress facilitates cleavage), and no critical shear-stress law based on external loading has been accepted...
Series: ASM Failure Analysis Case Histories
Volume: 3
Publisher: ASM International
Published: 01 December 2019
DOI: 10.31399/asm.fach.v03.c9001849
EISBN: 978-1-62708-241-9
... of severe sliding conditions probably accompanied by localized heating (high shear stresses, frictional, or adiabatic heat generation), see Fig. 8 . Surface-initiated spalling of hardened steel rolls was accomplished in several distinct phases, see also [ Ref. 2 ]: The microstructure...
Series: ASM Failure Analysis Case Histories
Publisher: ASM International
Published: 01 June 2019
DOI: 10.31399/asm.fach.aero.c0047986
EISBN: 978-1-62708-217-4
...-ring raceway. Metallographic examination of a circumferential section through the largest cavity revealed an elongated subsurface inclusion (arrow, Fig. 1d ). This inclusion was in the region of maximum shear stress in the bearing (approximately 0.1 mm, or 0.005 in., below the surface), which...